4(0.5x+3)=3x+12-x

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Solution for 4(0.5x+3)=3x+12-x equation: 



4(0.5x+3)=3x+12-x

We move all terms to the left:

4(0.5x+3)-(3x+12-x)=0

We add all the numbers together, and all the variables

4(0.5x+3)-(2x+12)=0

We multiply parentheses

0x-(2x+12)+12=0

We get rid of parentheses

0x-2x-12+12=0

We add all the numbers together, and all the variables

-x=0

x=0/-1

x=0

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