4(1+2)(-3)=5+c*1

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Solution for 4(1+2)(-3)=5+c*1 equation:


Simplifying
4(1 + 2)(-3) = 5 + c * 1

Combine like terms: 1 + 2 = 3
4(3)(-3) = 5 + c * 1

Multiply 4 * 3
12 * -3 = 5 + c * 1

Multiply 12 * -3
-36 = 5 + c * 1

Reorder the terms for easier multiplication:
-36 = 5 + 1c

Solving
-36 = 5 + 1c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
-36 + -1c = 5 + 1c + -1c

Combine like terms: 1c + -1c = 0
-36 + -1c = 5 + 0
-36 + -1c = 5

Add '36' to each side of the equation.
-36 + 36 + -1c = 5 + 36

Combine like terms: -36 + 36 = 0
0 + -1c = 5 + 36
-1c = 5 + 36

Combine like terms: 5 + 36 = 41
-1c = 41

Divide each side by '-1'.
c = -41

Simplifying
c = -41

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