4(1+2b)-5=-1+4(6+3b)

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Solution for 4(1+2b)-5=-1+4(6+3b) equation: 



4(1+2b)-5=-1+4(6+3b)

We move all terms to the left:

4(1+2b)-5-(-1+4(6+3b))=0

We add all the numbers together, and all the variables

4(2b+1)-(-1+4(3b+6))-5=0

We multiply parentheses

8b-(-1+4(3b+6))+4-5=0



We calculate terms in parentheses: -(-1+4(3b+6)), so:

-1+4(3b+6)

determiningTheFunctionDomain
4(3b+6)-1

We multiply parentheses

12b+24-1

We add all the numbers together, and all the variables

12b+23

Back to the equation:

-(12b+23)



We add all the numbers together, and all the variables

8b-(12b+23)-1=0

We get rid of parentheses

8b-12b-23-1=0

We add all the numbers together, and all the variables

-4b-24=0

We move all terms containing b to the left, all other terms to the right

-4b=24

b=24/-4

b=-6

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