4(1+2m)=1/2(6+16m)

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Solution for 4(1+2m)=1/2(6+16m) equation: 



4(1+2m)=1/2(6+16m)

We move all terms to the left:

4(1+2m)-(1/2(6+16m))=0



Domain of the equation: 2(6+16m))!=0

m∈R



We add all the numbers together, and all the variables

4(2m+1)-(1/2(16m+6))=0

We multiply parentheses

8m-(1/2(16m+6))+4=0

We multiply all the terms by the denominator


8m*2(16m+6))-(1+4*2(16m+6))=0

Wy multiply elements

16m^2(1+8m(1=0

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