4(1+2x)=6(x-1)+3x

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Solution for 4(1+2x)=6(x-1)+3x equation: 



4(1+2x)=6(x-1)+3x

We move all terms to the left:

4(1+2x)-(6(x-1)+3x)=0

We add all the numbers together, and all the variables

4(2x+1)-(6(x-1)+3x)=0

We multiply parentheses

8x-(6(x-1)+3x)+4=0



We calculate terms in parentheses: -(6(x-1)+3x), so:

6(x-1)+3x

We add all the numbers together, and all the variables

3x+6(x-1)

We multiply parentheses

3x+6x-6

We add all the numbers together, and all the variables

9x-6

Back to the equation:

-(9x-6)



We get rid of parentheses

8x-9x+6+4=0

We add all the numbers together, and all the variables

-1x+10=0

We move all terms containing x to the left, all other terms to the right

-x=-10

x=-10/-1

x=+10

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