4(1+3a)-4=27+3a

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Solution for 4(1+3a)-4=27+3a equation: 



4(1+3a)-4=27+3a

We move all terms to the left:

4(1+3a)-4-(27+3a)=0

We add all the numbers together, and all the variables

4(3a+1)-(3a+27)-4=0

We multiply parentheses

12a-(3a+27)+4-4=0

We get rid of parentheses

12a-3a-27+4-4=0

We add all the numbers together, and all the variables

9a-27=0

We move all terms containing a to the left, all other terms to the right

9a=27

a=27/9

a=3

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