4(1+3b)=2(b-2)

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Solution for 4(1+3b)=2(b-2) equation:


Simplifying
4(1 + 3b) = 2(b + -2)
(1 * 4 + 3b * 4) = 2(b + -2)
(4 + 12b) = 2(b + -2)

Reorder the terms:
4 + 12b = 2(-2 + b)
4 + 12b = (-2 * 2 + b * 2)
4 + 12b = (-4 + 2b)

Solving
4 + 12b = -4 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
4 + 12b + -2b = -4 + 2b + -2b

Combine like terms: 12b + -2b = 10b
4 + 10b = -4 + 2b + -2b

Combine like terms: 2b + -2b = 0
4 + 10b = -4 + 0
4 + 10b = -4

Add '-4' to each side of the equation.
4 + -4 + 10b = -4 + -4

Combine like terms: 4 + -4 = 0
0 + 10b = -4 + -4
10b = -4 + -4

Combine like terms: -4 + -4 = -8
10b = -8

Divide each side by '10'.
b = -0.8

Simplifying
b = -0.8

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