4(1+3b)=2(b-3)

Solution for 4(1+3b)=2(b-3) equation:

4(1+3b)=2(b-3)

We move all terms to the left:

4(1+3b)-(2(b-3))=0

We add all the numbers together, and all the variables

4(3b+1)-(2(b-3))=0

We multiply parentheses

12b-(2(b-3))+4=0


We calculate terms in parentheses: -(2(b-3)), so:

2(b-3)

We multiply parentheses

2b-6

Back to the equation:

-(2b-6)


We get rid of parentheses

12b-2b+6+4=0

We add all the numbers together, and all the variables

10b+10=0

We move all terms containing b to the left, all other terms to the right

10b=-10

b=-10/10

b=-1