4(1+3d)=28

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Solution for 4(1+3d)=28 equation: 



4(1+3d)=28

We move all terms to the left:

4(1+3d)-(28)=0

We add all the numbers together, and all the variables

4(3d+1)-28=0

We multiply parentheses

12d+4-28=0

We add all the numbers together, and all the variables

12d-24=0

We move all terms containing d to the left, all other terms to the right

12d=24

d=24/12

d=2

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