4(1+3n)=4(n+3)+6n

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Solution for 4(1+3n)=4(n+3)+6n equation: 



4(1+3n)=4(n+3)+6n

We move all terms to the left:

4(1+3n)-(4(n+3)+6n)=0

We add all the numbers together, and all the variables

4(3n+1)-(4(n+3)+6n)=0

We multiply parentheses

12n-(4(n+3)+6n)+4=0



We calculate terms in parentheses: -(4(n+3)+6n), so:

4(n+3)+6n

We add all the numbers together, and all the variables

6n+4(n+3)

We multiply parentheses

6n+4n+12

We add all the numbers together, and all the variables

10n+12

Back to the equation:

-(10n+12)



We get rid of parentheses

12n-10n-12+4=0

We add all the numbers together, and all the variables

2n-8=0

We move all terms containing n to the left, all other terms to the right

2n=8

n=8/2

n=4

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