4(1+3n)=4n+20

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Solution for 4(1+3n)=4n+20 equation: 



4(1+3n)=4n+20

We move all terms to the left:

4(1+3n)-(4n+20)=0

We add all the numbers together, and all the variables

4(3n+1)-(4n+20)=0

We multiply parentheses

12n-(4n+20)+4=0

We get rid of parentheses

12n-4n-20+4=0

We add all the numbers together, and all the variables

8n-16=0

We move all terms containing n to the left, all other terms to the right

8n=16

n=16/8

n=2

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