4(1+3p)=28

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Solution for 4(1+3p)=28 equation: 



4(1+3p)=28

We move all terms to the left:

4(1+3p)-(28)=0

We add all the numbers together, and all the variables

4(3p+1)-28=0

We multiply parentheses

12p+4-28=0

We add all the numbers together, and all the variables

12p-24=0

We move all terms containing p to the left, all other terms to the right

12p=24

p=24/12

p=2

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