4(1+3r)=-68

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Solution for 4(1+3r)=-68 equation: 



4(1+3r)=-68

We move all terms to the left:

4(1+3r)-(-68)=0

We add all the numbers together, and all the variables

4(3r+1)-(-68)=0

We add all the numbers together, and all the variables

4(3r+1)+68=0

We multiply parentheses

12r+4+68=0

We add all the numbers together, and all the variables

12r+72=0

We move all terms containing r to the left, all other terms to the right

12r=-72

r=-72/12

r=-6

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