4(1+3r)=-8(r-8)

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Solution for 4(1+3r)=-8(r-8) equation: 



4(1+3r)=-8(r-8)

We move all terms to the left:

4(1+3r)-(-8(r-8))=0

We add all the numbers together, and all the variables

4(3r+1)-(-8(r-8))=0

We multiply parentheses

12r-(-8(r-8))+4=0



We calculate terms in parentheses: -(-8(r-8)), so:

-8(r-8)

We multiply parentheses

-8r+64

Back to the equation:

-(-8r+64)



We get rid of parentheses

12r+8r-64+4=0

We add all the numbers together, and all the variables

20r-60=0

We move all terms containing r to the left, all other terms to the right

20r=60

r=60/20

r=3

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