4(1+3x)=8(4x+8)

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Solution for 4(1+3x)=8(4x+8) equation: 



4(1+3x)=8(4x+8)

We move all terms to the left:

4(1+3x)-(8(4x+8))=0

We add all the numbers together, and all the variables

4(3x+1)-(8(4x+8))=0

We multiply parentheses

12x-(8(4x+8))+4=0



We calculate terms in parentheses: -(8(4x+8)), so:

8(4x+8)

We multiply parentheses

32x+64

Back to the equation:

-(32x+64)



We get rid of parentheses

12x-32x-64+4=0

We add all the numbers together, and all the variables

-20x-60=0

We move all terms containing x to the left, all other terms to the right

-20x=60

x=60/-20

x=-3

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