4(1+3y)=2(6y+2)

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Solution for 4(1+3y)=2(6y+2) equation: 



4(1+3y)=2(6y+2)

We move all terms to the left:

4(1+3y)-(2(6y+2))=0

We add all the numbers together, and all the variables

4(3y+1)-(2(6y+2))=0

We multiply parentheses

12y-(2(6y+2))+4=0



We calculate terms in parentheses: -(2(6y+2)), so:

2(6y+2)

We multiply parentheses

12y+4

Back to the equation:

-(12y+4)



We get rid of parentheses

12y-12y-4+4=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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