4(1+5a)=4(2a+3a+1)

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Solution for 4(1+5a)=4(2a+3a+1) equation: 



4(1+5a)=4(2a+3a+1)

We move all terms to the left:

4(1+5a)-(4(2a+3a+1))=0

We add all the numbers together, and all the variables

4(5a+1)-(4(5a+1))=0

We multiply parentheses

20a-(4(5a+1))+4=0



We calculate terms in parentheses: -(4(5a+1)), so:

4(5a+1)

We multiply parentheses

20a+4

Back to the equation:

-(20a+4)



We get rid of parentheses

20a-20a-4+4=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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