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4(1+5k)=-4+4(3k-6)
We move all terms to the left:
4(1+5k)-(-4+4(3k-6))=0
We add all the numbers together, and all the variables
4(5k+1)-(-4+4(3k-6))=0
We multiply parentheses
20k-(-4+4(3k-6))+4=0
We calculate terms in parentheses: -(-4+4(3k-6)), so:We get rid of parentheses
-4+4(3k-6)
determiningTheFunctionDomain 4(3k-6)-4
We multiply parentheses
12k-24-4
We add all the numbers together, and all the variables
12k-28
Back to the equation:
-(12k-28)
20k-12k+28+4=0
We add all the numbers together, and all the variables
8k+32=0
We move all terms containing k to the left, all other terms to the right
8k=-32
k=-32/8
k=-4
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