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4(1+5x)=6+2(12+x)+4x
We move all terms to the left:
4(1+5x)-(6+2(12+x)+4x)=0
We add all the numbers together, and all the variables
4(5x+1)-(6+2(x+12)+4x)=0
We multiply parentheses
20x-(6+2(x+12)+4x)+4=0
We calculate terms in parentheses: -(6+2(x+12)+4x), so:We get rid of parentheses
6+2(x+12)+4x
determiningTheFunctionDomain 2(x+12)+4x+6
We add all the numbers together, and all the variables
4x+2(x+12)+6
We multiply parentheses
4x+2x+24+6
We add all the numbers together, and all the variables
6x+30
Back to the equation:
-(6x+30)
20x-6x-30+4=0
We add all the numbers together, and all the variables
14x-26=0
We move all terms containing x to the left, all other terms to the right
14x=26
x=26/14
x=1+6/7
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