4(1+6a)=3(3a-2)+5a

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Solution for 4(1+6a)=3(3a-2)+5a equation: 



4(1+6a)=3(3a-2)+5a

We move all terms to the left:

4(1+6a)-(3(3a-2)+5a)=0

We add all the numbers together, and all the variables

4(6a+1)-(3(3a-2)+5a)=0

We multiply parentheses

24a-(3(3a-2)+5a)+4=0



We calculate terms in parentheses: -(3(3a-2)+5a), so:

3(3a-2)+5a

We add all the numbers together, and all the variables

5a+3(3a-2)

We multiply parentheses

5a+9a-6

We add all the numbers together, and all the variables

14a-6

Back to the equation:

-(14a-6)



We get rid of parentheses

24a-14a+6+4=0

We add all the numbers together, and all the variables

10a+10=0

We move all terms containing a to the left, all other terms to the right

10a=-10

a=-10/10

a=-1

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