4(1+6a)=3(3a-2)+5a

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Solution for 4(1+6a)=3(3a-2)+5a equation:



4(1+6a)=3(3a-2)+5a
We move all terms to the left:
4(1+6a)-(3(3a-2)+5a)=0
We add all the numbers together, and all the variables
4(6a+1)-(3(3a-2)+5a)=0
We multiply parentheses
24a-(3(3a-2)+5a)+4=0
We calculate terms in parentheses: -(3(3a-2)+5a), so:
3(3a-2)+5a
We add all the numbers together, and all the variables
5a+3(3a-2)
We multiply parentheses
5a+9a-6
We add all the numbers together, and all the variables
14a-6
Back to the equation:
-(14a-6)
We get rid of parentheses
24a-14a+6+4=0
We add all the numbers together, and all the variables
10a+10=0
We move all terms containing a to the left, all other terms to the right
10a=-10
a=-10/10
a=-1

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