4(1+7c)=-35

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Solution for 4(1+7c)=-35 equation: 



4(1+7c)=-35

We move all terms to the left:

4(1+7c)-(-35)=0

We add all the numbers together, and all the variables

4(7c+1)-(-35)=0

We add all the numbers together, and all the variables

4(7c+1)+35=0

We multiply parentheses

28c+4+35=0

We add all the numbers together, and all the variables

28c+39=0

We move all terms containing c to the left, all other terms to the right

28c=-39

c=-39/28

c=-1+11/28

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