4(1+b)=19+b

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Solution for 4(1+b)=19+b equation: 



4(1+b)=19+b

We move all terms to the left:

4(1+b)-(19+b)=0

We add all the numbers together, and all the variables

4(b+1)-(b+19)=0

We multiply parentheses

4b-(b+19)+4=0

We get rid of parentheses

4b-b-19+4=0

We add all the numbers together, and all the variables

3b-15=0

We move all terms containing b to the left, all other terms to the right

3b=15

b=15/3

b=5

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