4(1+b)=19+b

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Solution for 4(1+b)=19+b equation:



4(1+b)=19+b
We move all terms to the left:
4(1+b)-(19+b)=0
We add all the numbers together, and all the variables
4(b+1)-(b+19)=0
We multiply parentheses
4b-(b+19)+4=0
We get rid of parentheses
4b-b-19+4=0
We add all the numbers together, and all the variables
3b-15=0
We move all terms containing b to the left, all other terms to the right
3b=15
b=15/3
b=5

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