4(1+c)=3(c+1)

Solution for 4(1+c)=3(c+1) equation:

Simplifying
4(1 + c) = 3(c + 1)
(1 * 4 + c * 4) = 3(c + 1)
(4 + 4c) = 3(c + 1)

Reorder the terms:
4 + 4c = 3(1 + c)
4 + 4c = (1 * 3 + c * 3)
4 + 4c = (3 + 3c)

Solving
4 + 4c = 3 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
4 + 4c + -3c = 3 + 3c + -3c

Combine like terms: 4c + -3c = 1c
4 + 1c = 3 + 3c + -3c

Combine like terms: 3c + -3c = 0
4 + 1c = 3 + 0
4 + 1c = 3

Add '-4' to each side of the equation.
4 + -4 + 1c = 3 + -4

Combine like terms: 4 + -4 = 0
0 + 1c = 3 + -4
1c = 3 + -4

Combine like terms: 3 + -4 = -1
1c = -1

Divide each side by '1'.
c = -1

Simplifying
c = -1