4(1+c)=3(c-2)

Solution for 4(1+c)=3(c-2) equation:

Simplifying
4(1 + c) = 3(c + -2)
(1 * 4 + c * 4) = 3(c + -2)
(4 + 4c) = 3(c + -2)

Reorder the terms:
4 + 4c = 3(-2 + c)
4 + 4c = (-2 * 3 + c * 3)
4 + 4c = (-6 + 3c)

Solving
4 + 4c = -6 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
4 + 4c + -3c = -6 + 3c + -3c

Combine like terms: 4c + -3c = 1c
4 + 1c = -6 + 3c + -3c

Combine like terms: 3c + -3c = 0
4 + 1c = -6 + 0
4 + 1c = -6

Add '-4' to each side of the equation.
4 + -4 + 1c = -6 + -4

Combine like terms: 4 + -4 = 0
0 + 1c = -6 + -4
1c = -6 + -4

Combine like terms: -6 + -4 = -10
1c = -10

Divide each side by '1'.
c = -10

Simplifying
c = -10