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4(1+x)=3(2+x)
We move all terms to the left:
4(1+x)-(3(2+x))=0
We add all the numbers together, and all the variables
4(x+1)-(3(x+2))=0
We multiply parentheses
4x-(3(x+2))+4=0
We calculate terms in parentheses: -(3(x+2)), so:We get rid of parentheses
3(x+2)
We multiply parentheses
3x+6
Back to the equation:
-(3x+6)
4x-3x-6+4=0
We add all the numbers together, and all the variables
x-2=0
We move all terms containing x to the left, all other terms to the right
x=2
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