4(1-3D)=2(-6d+2)

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Solution for 4(1-3D)=2(-6d+2) equation:



4(1-3)=2(-6D+2)
We move all terms to the left:
4(1-3)-(2(-6D+2))=0
We add all the numbers together, and all the variables
-(2(-6D+2))+4(-2)=0
We add all the numbers together, and all the variables
-(2(-6D+2))-8=0
We calculate terms in parentheses: -(2(-6D+2)), so:
2(-6D+2)
We multiply parentheses
-12D+4
Back to the equation:
-(-12D+4)
We get rid of parentheses
12D-4-8=0
We add all the numbers together, and all the variables
12D-12=0
We move all terms containing D to the left, all other terms to the right
12D=12
D=12/12
D=1

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