4(1-3n)=2n-3x3/2

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Solution for 4(1-3n)=2n-3x3/2 equation: 


x in (-oo:+oo)

4*(1-(3*n)) = 2*n-((3*x^3)/2) // - 2*n-((3*x^3)/2)

4*(1-(3*n))-(2*n)+(3*x^3)/2 = 0

4*(1-3*n)-2*n+(3*x^3)/2 = 0

(2*4*(1-3*n))/2+(-2*2*n)/2+(3*x^3)/2 = 0

2*4*(1-3*n)-2*2*n+3*x^3 = 0

3*x^3-28*n+8 = 0

(3*x^3-28*n+8)/2 = 0

(3*x^3-28*n+8)/2 = 0 // * 2

3*x^3-28*n+8 = 0

3*x^3 = -(8-28*n) // : 3

x^3 = (-(8-28*n))/3

x^3 = (-(8-28*n))/3 // ^ 1/3

x = (-(8-28*n)^(1/3))/(3^(1/3))

x = (-(8-28*n)^(1/3))/(3^(1/3))

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