4(1-3x)+3(x-3)=-6(x-6)+6

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Solution for 4(1-3x)+3(x-3)=-6(x-6)+6 equation: 



4(1-3x)+3(x-3)=-6(x-6)+6

We move all terms to the left:

4(1-3x)+3(x-3)-(-6(x-6)+6)=0

We add all the numbers together, and all the variables

4(-3x+1)+3(x-3)-(-6(x-6)+6)=0

We multiply parentheses

-12x+3x-(-6(x-6)+6)+4-9=0



We calculate terms in parentheses: -(-6(x-6)+6), so:

-6(x-6)+6

We multiply parentheses

-6x+36+6

We add all the numbers together, and all the variables

-6x+42

Back to the equation:

-(-6x+42)



We add all the numbers together, and all the variables

-9x-(-6x+42)-5=0

We get rid of parentheses

-9x+6x-42-5=0

We add all the numbers together, and all the variables

-3x-47=0

We move all terms containing x to the left, all other terms to the right

-3x=47

x=47/-3

x=-15+2/3

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