4(1-c)+3c=-2(c+1)

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Solution for 4(1-c)+3c=-2(c+1) equation: 



4(1-c)+3c=-2(c+1)

We move all terms to the left:

4(1-c)+3c-(-2(c+1))=0

We add all the numbers together, and all the variables

4(-1c+1)+3c-(-2(c+1))=0

We add all the numbers together, and all the variables

3c+4(-1c+1)-(-2(c+1))=0

We multiply parentheses

3c-4c-(-2(c+1))+4=0



We calculate terms in parentheses: -(-2(c+1)), so:

-2(c+1)

We multiply parentheses

-2c-2

Back to the equation:

-(-2c-2)



We add all the numbers together, and all the variables

-1c-(-2c-2)+4=0

We get rid of parentheses

-1c+2c+2+4=0

We add all the numbers together, and all the variables

c+6=0

We move all terms containing c to the left, all other terms to the right

c=-6

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