4(1-x)+2=-3(x/1)

Solution for 4(1-x)+2=-3(x/1) equation:

4(1-x)+2=-3(x/1)

We move all terms to the left:

4(1-x)+2-(-3(x/1))=0

We add all the numbers together, and all the variables

4(-1x+1)-(-3(+x/1))+2=0

We multiply parentheses

-4x-(-3(+x/1))+4+2=0

We multiply all the terms by the denominator


-4x*1))-(-3(+x+4*1))+2*1))=0

We add all the numbers together, and all the variables

-4x*1))-(-3(x+4))+2*1))=0

We add all the numbers together, and all the variables

-4x*1))-(-3(x=0

Wy multiply elements

-4x^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$