4(1-x)+3x=-29(x+1)

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Solution for 4(1-x)+3x=-29(x+1) equation: 



4(1-x)+3x=-29(x+1)

We move all terms to the left:

4(1-x)+3x-(-29(x+1))=0

We add all the numbers together, and all the variables

4(-1x+1)+3x-(-29(x+1))=0

We add all the numbers together, and all the variables

3x+4(-1x+1)-(-29(x+1))=0

We multiply parentheses

3x-4x-(-29(x+1))+4=0



We calculate terms in parentheses: -(-29(x+1)), so:

-29(x+1)

We multiply parentheses

-29x-29

Back to the equation:

-(-29x-29)



We add all the numbers together, and all the variables

-1x-(-29x-29)+4=0

We get rid of parentheses

-1x+29x+29+4=0

We add all the numbers together, and all the variables

28x+33=0

We move all terms containing x to the left, all other terms to the right

28x=-33

x=-33/28

x=-1+5/28

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