4(1-x)+3x=-3x-2(x+1)

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Solution for 4(1-x)+3x=-3x-2(x+1) equation: 



4(1-x)+3x=-3x-2(x+1)

We move all terms to the left:

4(1-x)+3x-(-3x-2(x+1))=0

We add all the numbers together, and all the variables

4(-1x+1)+3x-(-3x-2(x+1))=0

We add all the numbers together, and all the variables

3x+4(-1x+1)-(-3x-2(x+1))=0

We multiply parentheses

3x-4x-(-3x-2(x+1))+4=0



We calculate terms in parentheses: -(-3x-2(x+1)), so:

-3x-2(x+1)

We multiply parentheses

-3x-2x-2

We add all the numbers together, and all the variables

-5x-2

Back to the equation:

-(-5x-2)



We add all the numbers together, and all the variables

-1x-(-5x-2)+4=0

We get rid of parentheses

-1x+5x+2+4=0

We add all the numbers together, and all the variables

4x+6=0

We move all terms containing x to the left, all other terms to the right

4x=-6

x=-6/4

x=-1+1/2

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