4(1-x)-(3x+2)=6+8(x-8)

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Solution for 4(1-x)-(3x+2)=6+8(x-8) equation: 



4(1-x)-(3x+2)=6+8(x-8)

We move all terms to the left:

4(1-x)-(3x+2)-(6+8(x-8))=0

We add all the numbers together, and all the variables

4(-1x+1)-(3x+2)-(6+8(x-8))=0

We multiply parentheses

-4x-(3x+2)-(6+8(x-8))+4=0

We get rid of parentheses

-4x-3x-(6+8(x-8))-2+4=0



We calculate terms in parentheses: -(6+8(x-8)), so:

6+8(x-8)

determiningTheFunctionDomain
8(x-8)+6

We multiply parentheses

8x-64+6

We add all the numbers together, and all the variables

8x-58

Back to the equation:

-(8x-58)



We add all the numbers together, and all the variables

-7x-(8x-58)+2=0

We get rid of parentheses

-7x-8x+58+2=0

We add all the numbers together, and all the variables

-15x+60=0

We move all terms containing x to the left, all other terms to the right

-15x=-60

x=-60/-15

x=+4

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