4(1-x)-(4x+2)=6+6(x-3)

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Solution for 4(1-x)-(4x+2)=6+6(x-3) equation: 



4(1-x)-(4x+2)=6+6(x-3)

We move all terms to the left:

4(1-x)-(4x+2)-(6+6(x-3))=0

We add all the numbers together, and all the variables

4(-1x+1)-(4x+2)-(6+6(x-3))=0

We multiply parentheses

-4x-(4x+2)-(6+6(x-3))+4=0

We get rid of parentheses

-4x-4x-(6+6(x-3))-2+4=0



We calculate terms in parentheses: -(6+6(x-3)), so:

6+6(x-3)

determiningTheFunctionDomain
6(x-3)+6

We multiply parentheses

6x-18+6

We add all the numbers together, and all the variables

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

-8x-(6x-12)+2=0

We get rid of parentheses

-8x-6x+12+2=0

We add all the numbers together, and all the variables

-14x+14=0

We move all terms containing x to the left, all other terms to the right

-14x=-14

x=-14/-14

x=1

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