4(1/2m+6)+18/6=m+3(3m+9)

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Solution for 4(1/2m+6)+18/6=m+3(3m+9) equation: 



4(1/2m+6)+18/6=m+3(3m+9)

We move all terms to the left:

4(1/2m+6)+18/6-(m+3(3m+9))=0



Domain of the equation: 2m+6)!=0

m∈R



We add all the numbers together, and all the variables

4(1/2m+6)-(m+3(3m+9))+3=0

We multiply parentheses

4m-(m+3(3m+9))+24+3=0



We calculate terms in parentheses: -(m+3(3m+9)), so:

m+3(3m+9)

We multiply parentheses

m+9m+27

We add all the numbers together, and all the variables

10m+27

Back to the equation:

-(10m+27)



We add all the numbers together, and all the variables

4m-(10m+27)+27=0

We get rid of parentheses

4m-10m-27+27=0

We add all the numbers together, and all the variables

-6m=0

m=0/-6

m=0

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