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4(1/2x+3=3x+12-x
We move all terms to the left:
4(1/2x+3-(3x+12-x)=0
Domain of the equation: 2x+3-(3x+12-x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x-(3x+12-x)!=-3
x∈R
4(1/2x+3-(2x+12)=0
We multiply all the terms by the denominator
4(1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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