4(1/2x+3=3x+12-x

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Solution for 4(1/2x+3=3x+12-x equation: 



4(1/2x+3=3x+12-x

We move all terms to the left:

4(1/2x+3-(3x+12-x)=0



Domain of the equation: 2x+3-(3x+12-x)!=0

We move all terms containing x to the left, all other terms to the right

2x-(3x+12-x)!=-3

x∈R



We add all the numbers together, and all the variables

4(1/2x+3-(2x+12)=0

We multiply all the terms by the denominator


4(1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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