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4(1/3)x=260
We move all terms to the left:
4(1/3)x-(260)=0
Domain of the equation: 3)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4(+1/3)x-260=0
We multiply parentheses
4x^2-260=0
a = 4; b = 0; c = -260;
Δ = b2-4ac
Δ = 02-4·4·(-260)
Δ = 4160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4160}=\sqrt{64*65}=\sqrt{64}*\sqrt{65}=8\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{65}}{2*4}=\frac{0-8\sqrt{65}}{8} =-\frac{8\sqrt{65}}{8} =-\sqrt{65} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{65}}{2*4}=\frac{0+8\sqrt{65}}{8} =\frac{8\sqrt{65}}{8} =\sqrt{65} $
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