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4(1/5x-8)=2/5(4x+1)
We move all terms to the left:
4(1/5x-8)-(2/5(4x+1))=0
Domain of the equation: 5x-8)!=0
x∈R
Domain of the equation: 5(4x+1))!=0We multiply parentheses
x∈R
4x-(2/5(4x+1))-32=0
We multiply all the terms by the denominator
4x*5(4x+1))-(2-32*5(4x+1))=0
Wy multiply elements
20x^2(4-160x(4=0
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