4(10-2y)=12y-20

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Solution for 4(10-2y)=12y-20 equation: 



4(10-2y)=12y-20

We move all terms to the left:

4(10-2y)-(12y-20)=0

We add all the numbers together, and all the variables

4(-2y+10)-(12y-20)=0

We multiply parentheses

-8y-(12y-20)+40=0

We get rid of parentheses

-8y-12y+20+40=0

We add all the numbers together, and all the variables

-20y+60=0

We move all terms containing y to the left, all other terms to the right

-20y=-60

y=-60/-20

y=+3

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