4(10-4(-4x-3))=64x+88

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Solution for 4(10-4(-4x-3))=64x+88 equation:


Simplifying
4(10 + -4(-4x + -3)) = 64x + 88

Reorder the terms:
4(10 + -4(-3 + -4x)) = 64x + 88
4(10 + (-3 * -4 + -4x * -4)) = 64x + 88
4(10 + (12 + 16x)) = 64x + 88

Combine like terms: 10 + 12 = 22
4(22 + 16x) = 64x + 88
(22 * 4 + 16x * 4) = 64x + 88
(88 + 64x) = 64x + 88

Reorder the terms:
88 + 64x = 88 + 64x

Add '-88' to each side of the equation.
88 + -88 + 64x = 88 + -88 + 64x

Combine like terms: 88 + -88 = 0
0 + 64x = 88 + -88 + 64x
64x = 88 + -88 + 64x

Combine like terms: 88 + -88 = 0
64x = 0 + 64x
64x = 64x

Add '-64x' to each side of the equation.
64x + -64x = 64x + -64x

Combine like terms: 64x + -64x = 0
0 = 64x + -64x

Combine like terms: 64x + -64x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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