4(10-x)=40+4x

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Solution for 4(10-x)=40+4x equation:



4(10-x)=40+4x
We move all terms to the left:
4(10-x)-(40+4x)=0
We add all the numbers together, and all the variables
4(-1x+10)-(4x+40)=0
We multiply parentheses
-4x-(4x+40)+40=0
We get rid of parentheses
-4x-4x-40+40=0
We add all the numbers together, and all the variables
-8x=0
x=0/-8
x=0

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