4(10a+3)=10(4a-6)

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Solution for 4(10a+3)=10(4a-6) equation:


Simplifying
4(10a + 3) = 10(4a + -6)

Reorder the terms:
4(3 + 10a) = 10(4a + -6)
(3 * 4 + 10a * 4) = 10(4a + -6)
(12 + 40a) = 10(4a + -6)

Reorder the terms:
12 + 40a = 10(-6 + 4a)
12 + 40a = (-6 * 10 + 4a * 10)
12 + 40a = (-60 + 40a)

Add '-40a' to each side of the equation.
12 + 40a + -40a = -60 + 40a + -40a

Combine like terms: 40a + -40a = 0
12 + 0 = -60 + 40a + -40a
12 = -60 + 40a + -40a

Combine like terms: 40a + -40a = 0
12 = -60 + 0
12 = -60

Solving
12 = -60

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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