4(10m-5)=25+2(40-5m)

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Solution for 4(10m-5)=25+2(40-5m) equation: 



4(10m-5)=25+2(40-5m)

We move all terms to the left:

4(10m-5)-(25+2(40-5m))=0

We add all the numbers together, and all the variables

4(10m-5)-(25+2(-5m+40))=0

We multiply parentheses

40m-(25+2(-5m+40))-20=0



We calculate terms in parentheses: -(25+2(-5m+40)), so:

25+2(-5m+40)

determiningTheFunctionDomain
2(-5m+40)+25

We multiply parentheses

-10m+80+25

We add all the numbers together, and all the variables

-10m+105

Back to the equation:

-(-10m+105)



We get rid of parentheses

40m+10m-105-20=0

We add all the numbers together, and all the variables

50m-125=0

We move all terms containing m to the left, all other terms to the right

50m=125

m=125/50

m=2+1/2

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