4(10x+3)=40x-5

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Solution for 4(10x+3)=40x-5 equation:


Simplifying
4(10x + 3) = 40x + -5

Reorder the terms:
4(3 + 10x) = 40x + -5
(3 * 4 + 10x * 4) = 40x + -5
(12 + 40x) = 40x + -5

Reorder the terms:
12 + 40x = -5 + 40x

Add '-40x' to each side of the equation.
12 + 40x + -40x = -5 + 40x + -40x

Combine like terms: 40x + -40x = 0
12 + 0 = -5 + 40x + -40x
12 = -5 + 40x + -40x

Combine like terms: 40x + -40x = 0
12 = -5 + 0
12 = -5

Solving
12 = -5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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