4(10x+5y)=40x+20y

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Solution for 4(10x+5y)=40x+20y equation:


Simplifying
4(10x + 5y) = 40x + 20y
(10x * 4 + 5y * 4) = 40x + 20y
(40x + 20y) = 40x + 20y

Add '-40x' to each side of the equation.
40x + -40x + 20y = 40x + -40x + 20y

Combine like terms: 40x + -40x = 0
0 + 20y = 40x + -40x + 20y
20y = 40x + -40x + 20y

Combine like terms: 40x + -40x = 0
20y = 0 + 20y
20y = 20y

Add '-20y' to each side of the equation.
20y + -20y = 20y + -20y

Combine like terms: 20y + -20y = 0
0 = 20y + -20y

Combine like terms: 20y + -20y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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