4(10x-5)=25+2(40-5x)

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Solution for 4(10x-5)=25+2(40-5x) equation:



4(10x-5)=25+2(40-5x)
We move all terms to the left:
4(10x-5)-(25+2(40-5x))=0
We add all the numbers together, and all the variables
4(10x-5)-(25+2(-5x+40))=0
We multiply parentheses
40x-(25+2(-5x+40))-20=0
We calculate terms in parentheses: -(25+2(-5x+40)), so:
25+2(-5x+40)
determiningTheFunctionDomain 2(-5x+40)+25
We multiply parentheses
-10x+80+25
We add all the numbers together, and all the variables
-10x+105
Back to the equation:
-(-10x+105)
We get rid of parentheses
40x+10x-105-20=0
We add all the numbers together, and all the variables
50x-125=0
We move all terms containing x to the left, all other terms to the right
50x=125
x=125/50
x=2+1/2

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