4(11v+12)=6(12-5v)-8v

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Solution for 4(11v+12)=6(12-5v)-8v equation: 



4(11v+12)=6(12-5v)-8v

We move all terms to the left:

4(11v+12)-(6(12-5v)-8v)=0

We add all the numbers together, and all the variables

4(11v+12)-(6(-5v+12)-8v)=0

We multiply parentheses

44v-(6(-5v+12)-8v)+48=0



We calculate terms in parentheses: -(6(-5v+12)-8v), so:

6(-5v+12)-8v

We add all the numbers together, and all the variables

-8v+6(-5v+12)

We multiply parentheses

-8v-30v+72

We add all the numbers together, and all the variables

-38v+72

Back to the equation:

-(-38v+72)



We get rid of parentheses

44v+38v-72+48=0

We add all the numbers together, and all the variables

82v-24=0

We move all terms containing v to the left, all other terms to the right

82v=24

v=24/82

v=12/41

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