4(12+5b)=288

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Solution for 4(12+5b)=288 equation: 



4(12+5b)=288

We move all terms to the left:

4(12+5b)-(288)=0

We add all the numbers together, and all the variables

4(5b+12)-288=0

We multiply parentheses

20b+48-288=0

We add all the numbers together, and all the variables

20b-240=0

We move all terms containing b to the left, all other terms to the right

20b=240

b=240/20

b=12

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