4(12+8b)=-12(b+3)+2b

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Solution for 4(12+8b)=-12(b+3)+2b equation:



4(12+8b)=-12(b+3)+2b
We move all terms to the left:
4(12+8b)-(-12(b+3)+2b)=0
We add all the numbers together, and all the variables
4(8b+12)-(-12(b+3)+2b)=0
We multiply parentheses
32b-(-12(b+3)+2b)+48=0
We calculate terms in parentheses: -(-12(b+3)+2b), so:
-12(b+3)+2b
We add all the numbers together, and all the variables
2b-12(b+3)
We multiply parentheses
2b-12b-36
We add all the numbers together, and all the variables
-10b-36
Back to the equation:
-(-10b-36)
We get rid of parentheses
32b+10b+36+48=0
We add all the numbers together, and all the variables
42b+84=0
We move all terms containing b to the left, all other terms to the right
42b=-84
b=-84/42
b=-2

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