4(12-2z)=3(2z+9)

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Solution for 4(12-2z)=3(2z+9) equation: 



4(12-2z)=3(2z+9)

We move all terms to the left:

4(12-2z)-(3(2z+9))=0

We add all the numbers together, and all the variables

4(-2z+12)-(3(2z+9))=0

We multiply parentheses

-8z-(3(2z+9))+48=0



We calculate terms in parentheses: -(3(2z+9)), so:

3(2z+9)

We multiply parentheses

6z+27

Back to the equation:

-(6z+27)



We get rid of parentheses

-8z-6z-27+48=0

We add all the numbers together, and all the variables

-14z+21=0

We move all terms containing z to the left, all other terms to the right

-14z=-21

z=-21/-14

z=1+1/2

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